• Problemesis 15 : H28, Emanuel NAVON
    Ce problème, qui a obtenu une 2° M.H., est complètement anticipé (position identique) par Bruno Stucker, 18° T.T. Mat 1989, Recommandé - This problem, which obtained a 2nd H.M., is completely anticipated (same position) by par Bruno Stucker, 18° T.T. Mat 1989, Recommandé.

  • Problemesis 39 : H315, Michael SHAPIRO
    Chris Feather signale que ce problème est anticipé par Zivko Janevski & Branko Koludrovic, feenschach 1982 ; le juge retire le H315 du jugement des aidés 2004.
    Chris Feather indicates that this problem is anticipated by Zivko Janevski & Branko Koludrovic, feenschach 1982 ; the judge removes H315 from his helpmates 2004 award.

    Zivko JANEVSKI
    Branko KOLUDROVIC
    feenschach 1982
    a) 1.b1=C b8=C 2.Ca3 Ca6‡
    b) 1.b1=F b8=F 2.Fh7 Fe5‡
    c) 1.b1=T b8=T 2.Tg1 Th8‡
    Rd4 Pb7 Pg2 Ph2 Tg5 + Rb4 Pb3 Pb2 Pd7 Ca4
    h‡2 (5+5) C+
    b) Rb4®h8
    c) Rb4®h2

  • Problemesis 39 : D96, Evgeni BOURD
    The author suggests the following version :

    D96v - Evgeni BOURD
    Problemesis 2004 (v)
    1.Da1! [2.Ca7‡]
    1...Fd6 2.Dh1‡
    1...Td6 2.Dc1‡

    1.Da2! [2.Ca7‡]
    1...Fd6 2.Dd5‡
    1...Td6 2.Dc4‡

    1.Da3! [2.Ca7‡]
    1...Fd6 2.Df3‡
    1...Td6 2.Dc3‡

    1.Da4! [2.Ca7‡]
    1...Fd6 2.d5‡
    1...Td6 2.Dc2‡
    Rb2 Pb4 Pd4 Da7 Tg5 Ff4 Cb5 Cf6 + Rc6 Pb7 Pb6 Dc8 Td8 Tg7 Ff8 Cb8
    ‡2 (8+8) C+
    4 solutions