JUGEMENT - AWARD :
‡2 PROBLEMESIS 2004,
par Miodrag MLADENOVIC

[2004] D70 ... D122
The overall quality of problems published during this time period was average. There were lots of problems with rude refutations and flight taking tries and keys. After reviewing all problems I decided to place in this award six problems.

1° Prix : Evgeni BOURD (D88)

Very nice problem showing reciprocally changed white mates after black bishop correction play. In every phase there are Somov mates. After black bishops move c6 become guarded by white rook. After random move there is a simple mate by white. After correction move there is a Somov block theme in both try and solution. Excellent combination. It's too bad that there is no set mate after 1…Kc6 and that move is refutation in try. Anyway this is the best problem competing in this tournament.

Evgeni BOURD
Problemesis 2004
1° Prix
1.Rh2? blocus
1...F~ a 2.Fe6‡ A
1...Fe4! b 2.Ce3‡ B
mais 1...R×c6!

1.Te7! blocus
1...F~ a 2.Ce3‡ B
1...Fe4! b 2.Fe6‡ A
1...R×c6 2.Fb7‡
Rh1 Pc6 Pf4 Tc1 Te1 Fa7 Fc8 Ca3 Cg2 + Rd5 Pd6 Pf5 Fc2
‡2 (9+4) C+

2° Prix : Evgeni BOURD (D122)

This problem shows "Le Grand" theme. There are lots of nice elements in this problem: Somov block by bBf4, self-pining, pin mate etc. Too bad that position is little bit heave. I hope that there is no direct anticipation of this mechanism.

Evgeni BOURD
Problemesis 2004
2° Prix
1...Fe3 b 2.Cc3‡ A

1.Df2? [2.Cc3‡ A]
1...F×e5 a 2.Ce7‡ B
mais 1...Fe3! b

1.Tf5! [2.Ce7‡ B]
1...F×e5 a 2.Cc3‡ A
1...b×c6+ 2.F×c6‡
Rb5 Pc6 Pc2 Pd6 Pd3 Pe5 Dh4 Te8 Tf6 Fd7 Cc8 Ce2 + Rd5 Pb7 Pc7 Pc5 Pf7 Pg5 Dh2 Ff4 Fg2 Ca6 Cd2
‡2 (12+11) C+

1° Mention d'Honneur : Bernard DELOBEL (D97)

Nice achievement showing Albino theme in three tries and solution. Although this is not an original idea and there are plenty of other examples I believe that this is an original mechanism. In originally published solution it's listed that there are three refutations by bSg2 but in my opinion it's a single refutation 1…S~! Since that's thematic defense in solution.

Bernard DELOBEL
Problemesis 2004
1° Mention d'Honneur
1.e×d3? [2.Df2‡]
mais 1...Tb4!

1.e×f3? [2.Df2‡]
mais 1...Db5!

1.e3? [2.Df2‡]
mais 1...C×h4!, Cf4!, Ce1!

1.e4! [2.Df2‡]
1...Tb4 2.F×d3‡
1...Db5 2.T×f3‡
1...C~ 2.Ce3‡
1...T×h1 2.D×g2‡
1...d2 2.F×c4‡
Rb1 Pc3 Pd4 Pe2 Db2 Tf6 Th1 Fa6 Fg3 Cd1 Ch4 + Rf1 Pd3 Pf3 Dh5 Tc4 Th2 Fg1 Cg2
‡2 (11+8) C+

2° Mention d'Honneur : Evgeni BOURD (D103)

"Dombrovskis" theme in tries plus two changed mates. Although this is thematically rich problem there are some details that are not so pleasant. Like one of the refutation is black king move on the flight square that there is no set mate. Then the key move captures black pawn and reduces number of possible black moves from 3 to 2.

Evgeni BOURD
Problemesis 2004
2° Mention d'Honneur
1.Fd3? [2.e3‡ A]
mais 1...b4! a

1.e3? [2.Fd3‡ B]
mais 1...Re2! b

1.Fd2? blocus
1...b4 a 2.e3‡ A
1...R×e2 b 2.Fd3‡ B
mais 1...c5!

1.T×c6! blocus
1...b4 2.Tc1‡
1...R×e2 2.D×b5‡
Rh1 Pe2 Pf3 Da6 Tb3 Tf6 Fa5 Fb1 Cb2 Ce4 + Rf1 Pb5 Pc6
‡2 (10+3) C+

1° Recommandé : Bernard DELOBEL (D79)

Mutate with unexpected nice key that is allowing black bishop to play some additional moves. There is a clear change of white mate after 1…e4. The change after bBd4 random move is not so clear since there is a dual in set play after 1…Bc5 and that's only move that is same in set and solution.

Bernard DELOBEL
Problemesis 2004
1° Recommandé
1...e4 2.D×d4‡
1...F×b6 2.Te4‡

1.Tc5! blocus
1...e4 2.Cc4‡
1...Fd~ 2.Tc3‡
1...F×c5 2.D×c5‡
1...Fh~ 2.Cg2;Cf5‡
1...f3 2.Dh6‡
Rb8 Pa4 Pb7 Pd5 Db6 Tc4 Fa8 Fe1 Cd2 Ch4 + Re3 Pa5 Pd3 Pe5 Pe2 Pf4 Fd4 Fh3
‡2 (10+8) C+

2° Recommandé : Vladimir KOZHAKIN (D76)

Excellent key move that gives 4 flights. However side play is not so nice. Although there are two tries declared by author they can hardly be counted for a tries since refutation is by black king escape on a flight square that is given by try move. I do not consider them as tries at all.

Vladimir KOZHAKIN
Problemesis 2004
2° Recommandé
1.Tf4? blocus
1...R×d5 2.Tf5‡
mais 1...R×d6!

1.Cb4? blocus
1...R×b4 2.Db5‡
mais 1...Rd4!

1.Ce5! blocus
1...Rd4 2.Dc4‡
1...Rb4 2.Db5‡
1...R×d6 2.Cd3‡
1...R×d5 2.Cc6‡
Rb2 Pa5 Pd6 Pd5 Pe6 Pf6 Pf3 De2 Tf5 Fd7 Fh2 Cc6 + Rc5 Pe3 Ph3
‡2 (12+3) C+

Merci à Miodrag pour son jugement qui deviendra définitif le 01-11-2005.
Réclamations à Christian Poisson.